In this article we are going to see , how to serialize the class object to XML and De-Serialize the xml object to Class. For That Let we take a Example that , Employee file List ,which will maintain the information about employees and there projects.
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Xml.Serialization;
using System.IO;
using System.Reflection;
namespace ConsoleApplication8
{
class Program
{
static void Main(string[] args)
{
Serialize();
EmployeeFile EmpFile = DeSerialize();
foreach (Employee
emp in EmpFile.Employees)
Console.WriteLine("Employee Name " + emp.Name);
Console.Read();
}
static EmployeeFile
DeSerialize()
{
XmlSerializer serialize=new
XmlSerializer(typeof(EmployeeFile));
TextReader reader=new
StreamReader(@"D:\EmployeeFileList.xml",true);
return (EmployeeFile)serialize.Deserialize(reader);
}
static void
Serialize()
{
EmployeeFile employeefilelist = new EmployeeFile();
Employee emp1 = new
Employee();
emp1.Name = "Suresh";
emp1.Address = "chennai";
emp1.Age = 22;
emp1.Projects.Add(new Project() { Domain = "Java",
Name = "Encryption Handling" });
emp1.Projects.Add(new Project() { Domain = "DotNet",
Name = "Automatic ReCycling" });
Employee emp2 = new
Employee();
emp2.Name = "Rajesh";
emp2.Address = "Chennai";
emp2.Age = 25;
emp2.Projects.Add(new Project() { Domain = "DotNet",
Name = "Custom Controls" });
emp2.Projects.Add(new Project() { Domain = "PHP",
Name = "Faster Browsing" });
employeefilelist.Employees.Add(emp1);
employeefilelist.Employees.Add(emp2);
XmlSerializer serialize = new
XmlSerializer(typeof(EmployeeFile));
TextWriter writer = new
StreamWriter(@"D:\EmployeeFileList.xml",
true);
serialize.Serialize(writer, employeefilelist);
writer.Close();
}
}
[Serializable]
public class Project
{
private string name;
[XmlAttribute]
public string Name
{
set { name = value; }
get { return name; }
}
private string
domain;
[XmlAttribute]
public string Domain
{
set
{
domain = value;
}
get
{
return domain;
}
}
}
[Serializable]
public class Employee
{
private string name;
[XmlAttribute]
public string Name
{
set { name = value; }
get { return name; }
}
private string
address;
[XmlAttribute]
public string Address
{
set { address = value;
}
get { return address;
}
}
private int age;
[XmlAttribute]
public int Age
{
set { age = value; }
get { return age; }
}
private List<Project> projects = new
List<Project>();
public List<Project> Projects
{
set { projects = value;
}
get { return
projects; }
}
}
[Serializable]
public class EmployeeFile
{
private List<Employee> employees = new
List<Employee>();
public List<Employee> Employees
{
set { employees = value;
}
get { return
employees; }
}
}
}
Output :
Serialize an Xml is Formed in Location D:\EmploeeeFileList.xml
DeSerialize the Xml and save the data in employeefile class object print the Employee name in Console:
Employee Name Suresh
Employee Name Rajesh
This article will explain you how to convert the xml to class object and from class object to xml.